0=3x^2-29x+70

Solution for 0=3x^2-29x+70 equation:

0=3x^2-29x+70

We move all terms to the left:

0-(3x^2-29x+70)=0

We add all the numbers together, and all the variables

-(3x^2-29x+70)=0

We get rid of parentheses

-3x^2+29x-70=0

a = -3; b = 29; c = -70;
Δ = b2-4ac
Δ = 292-4·(-3)·(-70)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-1}{2*-3}=\frac{-30}{-6}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+1}{2*-3}=\frac{-28}{-6}
=4+2/3
$